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2x^2=12.50
We move all terms to the left:
2x^2-(12.50)=0
We add all the numbers together, and all the variables
2x^2-(12.5)=0
We add all the numbers together, and all the variables
2x^2-12.5=0
a = 2; b = 0; c = -12.5;
Δ = b2-4ac
Δ = 02-4·2·(-12.5)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*2}=\frac{-10}{4} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*2}=\frac{10}{4} =2+1/2 $
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